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23 June, 14:02

What are the partial pressures of NH3 and H2S at equilibrium, that is, what are the values of PNH3 and PH2S, respectively? Enter the partial pressure of ammonia followed by the partial pressure of hydrogen sulfide numerically in atmospheres separated by a comma.

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  1. 23 June, 14:07
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    Ammonium bisulfide, NH4HS, forms ammonia, NH3, and hydrogen sulfide, H2S, through the reaction NH4HS (s) ⇄NH3 (g) + H2S (g) This reaction has a Kp value of 0.120 at 25°C.

    An empty 5.00-L flask is charged with 0.300 g of pure H2S (g), at 25°C

    Partial pressure of NH3 = 0.325 atm

    Partial pressure of H2S = 0.368 atm

    Explanation:

    Temperature = 25 °C = 298 K

    Volume = 5 L

    Mass of H2S = 0.30 g

    Moles of H2S = 0.30 / 34.08

    = 0.0088

    Using PV = nRT

    Initial pressure of H2S = 0.0088 * 0.0821 * 298 / 5

    = 0.043 atm

    Kp = 0.120

    (a). NH4HS (s) ⇄ NH3 (g) + H2S (g)

    Initial - 0.0 0.043

    Change - + x + x

    Equilibrium - x 0.043 + x

    Kp = P (NH3) * P (H2S)

    0.120 = x (0.043 + x)

    x = 0.325 atm

    Hence, at equilibrium:

    Partial pressure of NH3 = 0.325 atm

    Partial pressure of H2S = 0.043 + 0.325 = 0.368 atm
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