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Keely Koch
Chemistry
24 February, 05:11
How many grams of N are in 89.0 g of NH4NO3
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Hubby
24 February, 05:22
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Step 1; calculate the molar mass of NH4N03
molar mass of different element
N=14
H=1
O=16
therefore molar mass of NH4NO3 is 14+4+14+48 = 80g/mol
step 2:find the molar mass of N present in NH4NO3
That is 14+14 = 28g/mol
the mass is therefore
{ (28g/mol/80g/mol) x 89g} = 31.15g
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