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determine the longest wavelength of light required to remove an electron from a sample of potassium metal, if the binding energy for an electron in K is 1,76x10*3 kj/mol.

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  1. 8 July, 08:39
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    The wavelength of light is 68 nm.

    Explanation:

    Given dа ta:

    Binding energy of electron = 176 * 10³ Kj / mol or (1.76 * 10⁶ j/mol)

    Wavelength of light require to remove the electron = ?

    Solution:

    E = hc / λ

    h = planck constant (6.63*10⁻³⁴ J/s)

    c = speed of light = (3*10⁸ m/s)

    The energy require per electron is

    1.76 * 10⁶ j / 6.02 * 10²³ = 2.92 * 10⁻¹⁸ J

    Now we will put the values in formula,

    E = hc / λ

    λ = hc / E

    λ = 6.63*10⁻³⁴ m². kg. s⁻¹. 3*10⁸ m/s / 2.92 * 10⁻¹⁸ J

    λ = 19.89*10⁻²⁶ m / 2.92 * 10⁻¹⁸ (m². kg. s⁻² = J)

    λ = 6.8 * 10⁻⁸ m

    λ = 6.8 * 10⁻⁸ * 10⁹

    λ = 68 nm
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