Toluene, c6h5ch3, is a liquid compound similar to benzene, c6h6. it is the starting material for other substances, including trinitrotoluene (tnt). find the molality of toluene in a solution that contains 35.6 g of toluene and 125 g of benzene.

Toulene = 35.6 g

Benzene = 125 g = 0.125 kg

Molecular weight of Toluene C6H5CH3 = 92.1g/mol

Moles of toulene = 35.6 g / 92.1 g/mol = 0.3865 mol

Now the molarity of the toulene in the given solution = 0.3865 / 0.125 = 3.092 m

Molarity of C6H5CH3 = 3.092 m