Consider the second-order decomposition of nitroysl chloride: 2NOCl (g) → 2NO (g) + Cl2 (g) At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 80 torr to decay to 23.7 torr?

Question

Houston Kelley

Chemistry

16 December, 04:09

Consider the second-order decomposition of nitroysl chloride: 2NOCl (g) → 2NO (g) + Cl2 (g) At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 80 torr to decay to 23.7 torr?

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Steven Barr · Answer 1

4.66 s

Explanation:

The reaction follows a second-order

Rate = kP^2 = change in pressure/time

k = 15.4 atm^-1s^-1

Po = 80 torr = 80/760 = 0.1053 atm

P = 23.7 torr = 23.7/760 = 0.0312 atm

Change in pressure = 0.1053 - 0.0312 = 0.0741 atm

15.4*0.0312^2 = 0.0741/time

time = 0.0741/0.0159 = 4.66 s