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19 November, 19:46

For the chemical reaction Na 2 CO 3 + Ca (NO 3) 2 ⟶ CaCO 3 + 2 NaNO 3 how many moles of calcium carbonate will be produced from 91.9 g of sodium carbonate? moles of calcium carbonate:

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  1. 19 November, 19:58
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    Na2CO3 mol = mass/rfm

    = 91.9 / (23+23+12+16+16+16)

    = 91.9/106

    =919/1060 or roughly 0.867

    Mole ratio of sodium carbonate to calcium carbonate is 1:1

    Therefore calcium carbonate mol = mass/rfm

    919/1060 = mass / (40+12+16+16+16)

    919/1060 = mass / 100

    Mass = 919/1060 x 100

    = 4595/53 or 86.7g to 3 significant figures
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