When hydrogen burns, water vapor is produced. the equation is 2h2 (g) + o2 (g) → 2h2o (g). if 12 l of oxygen are consumed at stp, what volume of water vapor is produced?

Question

Donna Christian

Chemistry

29 April, 08:20

When hydrogen burns, water vapor is produced. the equation is 2h2 (g) + o2 (g) → 2h2o (g). if 12 l of oxygen are consumed at stp, what volume of water vapor is produced?

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Answers (1)

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Rory · Answer 1

The volume of water vapor produced if 12 l of oxygen are consumed at STP is calculated as follows

2H2 (g) + O2 (g) = 2H2O

by use of mole ratio between O2 to H2O which is 1:2 the number of liters of H2O produced is therefore

= 2/1 x12 L = 24 L