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15 July, 14:40

You are given 450.0 g of a 0.7500 molal solution of acetone dissolved in water. how many grams of acetone are in this amount of solution?

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  1. 15 July, 15:00
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    Molality is the number of moles dissolved in one kilogram of solvent.

    m = n/kg of solvent

    n = mass of solute / molar mass of solute

    Acetone's chemical formula is C3H6O. Therefore, its molar mass = 12*3 + 6*1 + 1*16 = 58g = 0.058kg

    n = mass of solute / 0.058

    We have the molality = 0.7500 and the mass of solution = mass of solvent + mass of solute = 450 g = 0.45 kg

    Therfore, mass of solvet = 0.45 - mass of solute

    0.75 = n / 0.45 - mass of solute

    0.75 = (mass of solute / 0.058) / (0.45 - mass of solute)

    Let mass of solute = x

    0.75 = (x/0.058) / (0.45 - x)

    0.3375 - 0.75x = x/0.058

    x = 0.019575 - 0.0435x

    1.0435x = 0.019575

    x = 0.01875 kg

    mass of acetone = 0.01875 kg = 18.75 grams
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