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The enthalpy of formation of CO2 at 25oC is - 393.51 kJ/mol. What is the enthalpy of formation at 500 oC?

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  1. 3 July, 15:26
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    -375.9_KJ / (mol)

    Explanation:

    H (T2) ≈ H (T1) + CPΔT

    Specific heat of Carbon is 0.71 J/g K.

    At 283.15 the heat capacity is 37.12 J / (mol*K)

    Kirchhoff's law

    H (T2) ≈ H (T1) + CPΔT

    Where

    H (T1) and H (T2) are the heat of formation of CO2 at temperatures T1 and T2

    CP is the heat capacity

    Thus we have and ΔT is the temperature change

    H (T2) ≈ - 393.51*10^3+CP * (500-25)

    = - 393.51*10^3+37.12 * (500-25)

    = - 375878 J / (mol)

    = - 375.9KJ / (mol)
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