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21 April, 00:16

NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)

Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?

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  1. 21 April, 00:19
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    Moles=volume*concentration

    =0.1*.83

    =.083 Moles of HC2H3O2

    Mole ratio between HC2H3O2 and CO2 is 1:1

    This means. 083 Moles of CO2

    Mass = Moles*Rfm of CO2

    =.083 * (12+16+16)

    =3.7grams
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