How much heat, in joules and in calories, must be added to a 75.0-g iron block with a specific heat of 0.449 j/g °c to increase its temperature from 25 °c to its melting temperature of 1535 °c?

Question

Sage Johns

Chemistry

6 December, 02:35

How much heat, in joules and in calories, must be added to a 75.0-g iron block with a specific heat of 0.449 j/g °c to increase its temperature from 25 °c to its melting temperature of 1535 °c?

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Answers (1)

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Megan Bean · Answer 1

The amount of heat needed would be the specific heat multiplied by the mass of the substance and the temperature difference. In this case, the mass would be 75.0-g, the specific heat would be 0.449 j/g °c, and the temperature difference would be 1535 - 25 = 1510

Then the calculation would be: 0.449 j/g °c * 75g * 1510°c = 50,849.25J

In calorie it would be: 50849.25J / 4.184J/cal = 12,153.26 calorie