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17 December, 16:22

The artificial sweetener aspartame (nutra-sweet) formula c14h18n2o5 is used to sweeten diet foods, coffee and soft drinks. how many moles of aspartame are present in 225 g of aspartame?

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  1. 17 December, 16:28
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    Answer is: 0,765 moles of aspartame.

    m (C₁₄H₁₈N₂O₅) = 225 g.

    M (C₁₄H₁₈N₂O₅) = 14·12 + 18·1 + 2·14 + 5·16 = 294 g/mol.

    n (C₁₄H₁₈N₂O₅) = m (C₁₄H₁₈N₂O₅) : M (C₁₄H₁₈N₂O₅) = 225 g : 294 g/mol.

    n (C₁₄H₁₈N₂O₅) = 0,765 mol.

    m - mass of aspartame.

    M - molar mass of aspartame.

    n - amount of substance of aspartame.
  2. 17 December, 16:29
    0
    0.765 moles.

    Let's calculate the molar mass of aspartame by starting with looking up the atomic weights of the involved elements:

    Atomic weight carbon = 12.0107

    Atomic weight hydrogen = 1.00794

    Atomic weight nitrogen = 14.0067

    Atomic weight oxygen = 15.999

    Molar mass aspartame = 14 * 12.0107 + 18 * 1.00794 + 2 * 14.0067 + 5 * 15.999 = 294.30112 g/mol

    Moles aspartame = 225 g / 294.30112 g/mol = 0.764523084 mol

    Rounding to 3 significant figures gives 0.765 moles.
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