The artificial sweetener aspartame (nutra-sweet) formula c14h18n2o5 is used to sweeten diet foods, coffee and soft drinks. how many moles of aspartame are present in 225 g of aspartame?

Answer is: 0,765 moles of aspartame.

m (C₁₄H₁₈N₂O₅) = 225 g.

M (C₁₄H₁₈N₂O₅) = 14·12 + 18·1 + 2·14 + 5·16 = 294 g/mol.

n (C₁₄H₁₈N₂O₅) = m (C₁₄H₁₈N₂O₅) : M (C₁₄H₁₈N₂O₅) = 225 g : 294 g/mol.

n (C₁₄H₁₈N₂O₅) = 0,765 mol.

m - mass of aspartame.

M - molar mass of aspartame.

n - amount of substance of aspartame.

0.765 moles.

Let's calculate the molar mass of aspartame by starting with looking up the atomic weights of the involved elements:

Atomic weight carbon = 12.0107

Atomic weight hydrogen = 1.00794

Atomic weight nitrogen = 14.0067

Atomic weight oxygen = 15.999

Molar mass aspartame = 14 * 12.0107 + 18 * 1.00794 + 2 * 14.0067 + 5 * 15.999 = 294.30112 g/mol

Moles aspartame = 225 g / 294.30112 g/mol = 0.764523084 mol

Rounding to 3 significant figures gives 0.765 moles.