If 0.899J of heat causes a 0,692 degree C temperature change, what mass of water

is present?

0.309g

Explanation:

The following were obtained from the question:

Q = 0.899J

ΔT = 0.692°C

C = 4.2J/g °C

M = ?

Q = MCΔT

M = Q / CΔT

M = 0.899 / (4.2x0.692)

M = 0.309g

The mass of the water is 0.309g