The constant-pressure specific heat of air at 25°C is 1.005 kJ/kg °C. Express this value in kJ/kg-K. J/g °C, kcal/kg-°C, and Btu/lbm-°F.

Question

Kenya Garrett

Chemistry

26 December, 17:53

The constant-pressure specific heat of air at 25°C is 1.005 kJ/kg °C. Express this value in kJ/kg-K. J/g °C, kcal/kg-°C, and Btu/lbm-°F.

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Emilio · Answer 1

Cp = 1.005 kJ/kg °C = 1.005 kJ / (kg*K) = 1.005 J/g°C = 4.206 J/g°C = 0.776 BTU/lb°F

Explanation:

for the specific heat

1) Cp = 1.005 kJ/kg °C * (1 °C / 1 K) (temperature differences) = 1.005 kJ / (kg*K)

2) Cp = 1.005 kJ/kg °C * (1000 J / kJ) * (1 kg/1000 gr) = 1.005 J/g°C

3) Cp = 1.005 kJ/kg °C * (4.186 kcal/kJ) = 4.206 J/g°C

4) Cp = 1.005 kJ/kg °C * (1 BTU/1.055 kJ) * (0.4535 kg/lb) * (1.8°C/°F) = 0.776 BTU/lb°F