Calculate the mass in grams of 1.2044 x 10^24 atoms of lead (Pb).

A.) 207.2 g

B.) 2.0 g

C.) 0.50 g

D.) 414.4 g

Question

Wifey

Chemistry

2 December, 15:04

Calculate the mass in grams of 1.2044 x 10^24 atoms of lead (Pb).

A.) 207.2 g

B.) 2.0 g

C.) 0.50 g

D.) 414.4 g

+2

Answers (1)

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Cross · Answer 1

Answer: 414.14g

Explanation:

From Avogadro's hypothesis, we understand that 1mole of a substance contains 6.02x10^23 atoms.

From the above, it is evident that 1mole of Pb will also contain 6.02x10^23 atoms.

1mole of Pb = 207g/mol

207g of Pb contains 6.02x10^23 atoms.

Therefore, Xg of Pb will contain 1.2044 x 10^24 atoms i. e

Xg of Pb = (207x1.2044x10^24) / 6.02x10^23 = 414.14g

Calculate the mass in grams of 1.2044 x 10^24 atoms of lead (Pb).A.) 207.2 gB.) 2.0 gC.) 0.50 gD.) 414.4 g

Calculate the mass in grams of 1.2044 x 10^24 atoms of lead (Pb).

A.) 207.2 g

B.) 2.0 g

C.) 0.50 g

D.) 414.4 g