Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.

Electronegativity difference of Na and F:

yes

no

Question

Dorian Allison

Chemistry

9 April, 04:05

Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.

Electronegativity difference of Na and F:

yes

no

+4

Answers (2)

Know the Answer?

Raegan · Answer 1

Yes. They will form an ionic bond.

Explanation:

Electronegativity of fluorine is 4 and of sodium is 0.9 so

the difference is 4 - 0.9 = 3.1.

Kramer · Answer 2

Yes

Explanation:

Electronegativity value of Flourine (F) = 3.98

Electronegativity value of Sodium (Na) = 0.93

Electronegativity difference = 3.98 - 0.93 = 3.05

Since the electronegativity difference is greater than 1.5, it means the bond formed would be an ionic bond.

Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.Electronegativity difference of Na and F:yesno

Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.

Electronegativity difference of Na and F:

yes

no