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9 April, 04:05

Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.

Electronegativity difference of Na and F:

yes

no

+4
Answers (2)
  1. 9 April, 04:15
    0
    Yes. They will form an ionic bond.

    Explanation:

    Electronegativity of fluorine is 4 and of sodium is 0.9 so

    the difference is 4 - 0.9 = 3.1.
  2. 9 April, 04:21
    0
    Yes

    Explanation:

    Electronegativity value of Flourine (F) = 3.98

    Electronegativity value of Sodium (Na) = 0.93

    Electronegativity difference = 3.98 - 0.93 = 3.05

    Since the electronegativity difference is greater than 1.5, it means the bond formed would be an ionic bond.
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Home » Chemistry » Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.
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