How many Moles of NAOH are present in 2.50L of 0.300 M NaOH?

0.75 moles NaOH

Explanation:

We are given;

Volume of NaOH solution = 2.5 Liters

Molarity of NaOH = 0.300 M

We are required to calculate the moles of NaOH

We need to establish the relationship between moles, molarity and volume of a solution.

That would be;

Concentration/molarity = Moles : Volume

Therefore;

Moles = Concentration * Volume

Thus;

Moles of NaOH = 0.300 moles * 2.50 L

= 0.75 moles

Therefore, the number of moles of NaOH is 0.75 moles