What is the limiting reactant if 0.5 g al is reacted with 3.5 g cucl2? take into account cucl2 is a dihydrate when calculating the molecular weight?

Question

Houston Rosales

Chemistry

20 December, 17:52

What is the limiting reactant if 0.5 g al is reacted with 3.5 g cucl2? take into account cucl2 is a dihydrate when calculating the molecular weight?

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Answers (1)

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Keely Banks · Answer 1

Answer is: CuCl₂·2H₂O is limiting reactant.

Chemical reaction: 3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 6H₂ O.

m (Al) = 0,5 g.

m (CuCl₂·2H₂O) = 3,5 g.

n (CuCl₂·2H₂O) = m (CuCl₂·2H₂O) : M (CuCl₂·2H₂O).

n (CuCl₂·2H₂O) = 3,5 g : 170,5 g/mol.

n (CuCl₂·2H₂O) = 0,0205 mol.

n (Al) = 0,5 g : 27 g/mol.

n (Al) = 0,0185 mol.

From chemical reaction: n (Al) : n (CuCl₂·2H₂O) = 2 : 3.

0,0185 mol : n (CuCl₂·2H₂O) = 2 : 3.

n (CuCl₂·2H₂O) = 0,02755 mol; there is no enough n (CuCl₂·2H₂O).