Ask Question
Today, 05:52

Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as, and not as) Ka

+1
Answers (1)
  1. Today, 06:02
    0
    Ka = ([H₃O⁺]. [F⁻]) / [HF]

    Explanation:

    HF is a weak acid which in water, keeps this equilibrium

    HF (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + F⁻ (aq) Ka

    2H₂O (l) ⇄ H₃O⁺ (l) + OH⁻ (aq) Kw

    HF is the weak acid

    F⁻ is the conjugate stron base

    Let's make the expression for K

    K = ([H₃O⁺]. [F⁻]) / [HF]. [H₂O]

    K. [H₂O] = ([H₃O⁺]. [F⁻]) / [HF]

    K. [H₂O] = Ka

    Ka, the acid dissociation constant, includes Kwater.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain more than ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers