Ask Question
20 August, 19:10

Aluminum metal and chlorine gas react to from aluminum chloride 2Al (s) + 3Cl2 (g) - -> Al2Cl6 (s) How many grams of Al2Cl6 can be produced from the reaction of 2.67 mol aluminum and 3.26 mol Cl2?

+1
Answers (1)
  1. 20 August, 19:18
    0
    290.1 grams.

    Explanation:

    2 Al + 3Cl2 - --> Al2Cl6

    2 moles of Al react with 3 moles of Cl2 to form 1 mole of Al2Cl6

    So 2.67 moles Al reacts with 3/2 * 2.67 moles Cl2 = 4 moles of chlorine. But we only have 3.26 moles of Cl2 so this will react with only part of the available Al.

    3.26 reacts with 2/3 * 3.26 = 2.173 moles of aluminium.

    So the number of moles of Al2Cl6 that can be produced = 2.173 * 1/2

    = 1.087 moles.

    = 1.087 * (2*26.98 + 6*35.45)

    = 290.1 grams.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Aluminum metal and chlorine gas react to from aluminum chloride 2Al (s) + 3Cl2 (g) - -> Al2Cl6 (s) How many grams of Al2Cl6 can be produced ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers