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11 July, 14:14

How many grams of lithium sulfide must be dissolved in 1600.0 g water to make a 2.0 molal solution?

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  1. 11 July, 14:19
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    Molality is the number of moles of solutes in 1 kg of solvent.

    the molality of solution to be prepared is 2.0 molal.

    therefore 2 moles in 1 kg water.

    the mass of Li₂S required is - 46 g/mol x 2.0 mol = 92 g

    the mass in 1 kg of solvent is - 92 g

    Therefore mass of Li₂S required in 1600.0 g is - 92 g/kg x 1.6 kg = 147.2 g
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