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22 December, 14:49

The pH of an aqueous solution is 4.32. What is the [OH-]?

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  1. 22 December, 15:11
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    2.10 x 10^-10 M. Ans

    pH + pOH = 14

    Where, pOH is the power of hydroxide ion concentration and pH is the power of concetration of the H + ion.

    Now, pOH = 14 - 4.32

    = 9.68

    Now, the concentration of [H+] is 10-7 M, then pH is 7 and for [OH-] = 10-7 M, the pOH is also 7.

    Now, pOH = - log[OH-]

    [OH-] = 10^ - pOH

    = 10^-9.68

    = 2.10 x 10^-10 M
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