A piece of hot metal is put into an equal mass of water. The water temperature rises 5o and the metal's temperature drops 10o. What is the specific heat of the metal?

The answer to your question is Cm = 2.093 J/kg°C

Explanation:

Data

mass metal = mass of water

Δ water = 5°

Δ metal = 10°

Cm = ?

Cw = 4.186 J/Kg°C

Formula

for metal for water

mCmΔTm = mCwΔTw

Cancel mass of metal

Cm ΔTm = CwΔTw

solve for Cm

Cm = (CwΔTw) / ΔTm

Substitution

Cm = (4.186 x 5) / 10

Simplification

Cm = 20.93 / 10

Result

Cm = 2.093 J/kg°C