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15 July, 18:42

If 3.48 g of copper are recovered at the end of this experiment after allowing 4.00 g of copper to react with nitric acid in reaction #1, what is the theoretical yield and the actual percent yield of the reaction?

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  1. 15 July, 18:53
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    The theoretical yield is = 4.00 g; this is because it was the original mass of copper that had to be recovered.

    The percentage yield = 87.0%

    calculation

    % yield = actual yield/theoretical yield x 100

    actual yield = 3.48

    5 yield is therefore = 3.48/4.00 x100 = 87.0 %
  2. 15 July, 19:01
    0
    Answer : The theoretical yield and actual yield of the reaction are 4.00 g and 3.48 g respectively.

    Explanation:

    Theoretical yield : It is calculated from the amount of the limiting reagent present in the reaction.

    Actual yield : It is experimentally determined. That means the amount obtained at the end of the experiment.

    From this we conclude that, 3.48 g is the actual yield of the reaction because this amount is obtained at the end of the experiment and 4.00 g is the theoretical yield of the reaction because this amount is used in the calculation that means it is a calculated amount.

    Hence, the theoretical yield and actual yield of the reaction are 4.00 g and 3.48 g respectively.
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