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21 March, 11:10

What is the molarity of a solution that is prepared by adding 57.1 g of toluene (c 7 h 8 ) (density = 0.867 g/ml) to a 250 ml volumetric flask, and then filling to the mark with benzene (c 6 h 6 ) (density = 0.876 g/ml) ?

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  1. 21 March, 11:19
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    2.48 mol/L.

    Explanation:

    The molarity of the solution can be expressed as the number of moles of solute in 1.0 liter of the solution, (M = n / V). It is also can be calculated from the relation:

    M = (mass / molar mass) solute x (1000 / V of solution)

    The solute is toluene and the solvent is benzene.

    mass of toluene (solute) = 57.1 g,

    molar mass of toluene (solute) = 92.14 g/mol.

    volume of the solution = 250 ml.

    ∴ M = (mass / molar mass) solute x (1000 / V of solution) = [ (57.1 g / 92.14 g/mol) x (1000 / 250 ml) ] = 2.48 mol/L.
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