How many moles of nitrate ions are present in exactly 275 ml of a 1.25 m copper (ii) nitrate solution, cu (no3) 2 (aq) ?

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Adriana Dickerson

Chemistry

30 March, 09:33

How many moles of nitrate ions are present in exactly 275 ml of a 1.25 m copper (ii) nitrate solution, cu (no3) 2 (aq) ?

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Sawyer Barton · Answer 1

The formula for copper nitrate is written as Cu (NO₃) ₂. The formula for nitrate is NO₃. So, that means that for every 1 mole of Cu (NO₃) ₂, there are 2 moles of NO₃. The ratio is 1:2. Also, the concentration in molarity is expressed as moles solute per liter solution. The solution is as follows:

Moles nitrate = 1.25 mol Cu (NO₃) ₂/L * 1 L/1000 mL * 275 mL * 2 mol NO₃/1mol Cu (NO₃) ₂ = 0.6875 moles