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26 September, 10:07

How many atoms are present in 179.0 g of iridium

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  1. 26 September, 10:13
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    Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We do as follows:

    179.0 g of iridium (1 mol / 192.217 g) (6.022 x 10^23 atoms / 1 mol) = 5.61 x 10^23 atoms of iridium

    Hope this answers the question.
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