Reactant A can participate in both of these reactions:

1) A + B - > C + D DeltaGrxn = - 15.6 kJ

2) A + E - > F + G deltaGrxn = - 20.5 kJ

Reaction 1 has a much higher rate than Reaction 2 under the same reaction conditions. Explain this observation in terms of activation energy.

Question

Asher Pearson

Chemistry

4 August, 07:16

Reactant A can participate in both of these reactions:

1) A + B - > C + D DeltaGrxn = - 15.6 kJ

2) A + E - > F + G deltaGrxn = - 20.5 kJ

Reaction 1 has a much higher rate than Reaction 2 under the same reaction conditions. Explain this observation in terms of activation energy.

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Answers (1)

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Frances Friedman · Answer 1

The activation energy is the amount of energy required to initiate a certain reaction. The activation energy may considered as an "energy barrier" that has to be overcome in order for a reaction to begin. If a reaction has a lower activation energy, then it will occur more easily and at a faster rate than a reaction with a higher activation energy. Therefore, the reason that reaction 1 is faster than reaction 2 is because it has a lower activation energy than reaction 2.

Reactant A can participate in both of these reactions:1) A + B - > C + D DeltaGrxn = - 15.6 kJ2) A + E - > F + G deltaGrxn = - 20.5 kJReaction 1 has a much higher rate than Reaction 2 under the same reaction conditions. Explain this observation in terms of activation energy.

Reactant A can participate in both of these reactions:

1) A + B - > C + D DeltaGrxn = - 15.6 kJ

2) A + E - > F + G deltaGrxn = - 20.5 kJ

Reaction 1 has a much higher rate than Reaction 2 under the same reaction conditions. Explain this observation in terms of activation energy.