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29 May, 00:46

If you had 10.00 mL of acetic acid that you titrated with. 100 M NaOH, and you used 45.15 mL of that base to get a light pink color, what is the concentration of your acetic acid?

A).904M

B).452M

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Answers (1)
  1. 29 May, 01:06
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    0.4515 M

    Explanation:

    In case of titration, the following formula can be used -

    M₁V₁ = M₂V₂

    where,

    M₁ = concentration of acid,

    V₁ = volume of acid,

    M₂ = concentration of base,

    V₂ = volume of base.

    from, the question,

    M₁ = ? M

    V₁ = 10.0 mL

    M₂ = 0.100 M

    V₂ = 45.15 mL

    Using the above formula, the molarity of acid, can be calculated as,

    M₁V₁ = M₂V₂

    M₁ * 10.0mL = 0.100 M * 45.15 mL

    M₁ = 0.4515 M

    Hence, the concentration of the acetic acid = 0.4515 M
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