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18 December, 15:48

How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?

My attempt at answering this:

Using the formula (Vi) (Mi) = (Vf) (Mf)

(Vi) (2M) = (100) (0.4) = 200-100 (final volume) = 100 ml

I am assuming you would add 100 ml of water to the 2 M MgSO4 200 ml to get the 0.4 M MgSO4 100 ml

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Answers (1)
  1. 18 December, 16:15
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    OK, so to answer this question, you will simply use the molality equation which is as follows:

    M1V1 = M2V2

    In the givens you have:

    M1 = 2M

    V1 is the unknown

    M2 = 0.4M

    V2 = 100 ml

    plug in the givens in the above equation:

    2 x V1 = 0.4 x 100

    therefore:

    V1 = 20 ml

    Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.
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