A solution of hydrocloric acid has a molarity of 2.25 M HCl. If a reaction requires 5.80 g of HCI, what

volume of a solution should be used? Assume a molecular mass of 36.45 g for the HCI.

Calculate the number of moles of solute required:

g)

(36.45 g/mol) =

mol HCI

DONE

0.071L

Explanation:

From the question given, we obtained the following dа ta:

Molarity of HCl = 2.25 M

Mass of HCl = 5.80g

Molar Mass of HCl = 36.45g/mol

Number of mole of HCl = ?

Number of mole = Mass / Molar Mass

Number of mole of HCl = 5.8/36.45 = 0.159mole

Now, we can obtain the volume required as follows:

Molarity = mole / Volume

Volume = mole / Molarity

Volume = 0.159mole / 2.25

Volume = 0.071L