29 August, 16:45
How many grams of Na2SO4 should be weighed out to prepare 0.5L of a 0.100M solution?
29 August, 18:38
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
First of all the molecular weight of Na2SO4 is 142.08 gram. Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08*0.1 = 14.208 gram Na2SO4
1 ml of solution contain 14.208:1000 = 0.014 gram
0.5L or 500ml of solution contain 0.014*500 = 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
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