How many grams of Na2SO4 should be weighed out to prepare 0.5L of a 0.100M solution?

7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.

Explanation:

First of all the molecular weight of Na2SO4 is 142.08 gram. Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.

According to the given question we have to prepare 0.100 M solution

1000 ml of solution contain 142.08*0.1 = 14.208 gram Na2SO4

1 ml of solution contain 14.208:1000 = 0.014 gram

0.5L or 500ml of solution contain 0.014*500 = 7gram Na2SO4.

So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.