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23 November, 06:55

A chemist requires 0.811 mol Na2CO3 for a reaction. How many grams does this correspond to?

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  1. 23 November, 07:23
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    Mol=mass in g:Mr

    Mass=mol*Mr

    =0.811 * (add up mass of all elements)

    =0.811 * (16*3+23*2+12)

    =85.966g
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