A student burns 1.50 mol C3H8 according to the following reaction:

C3H8 + 5O2 3CO2 + 4H2O.

How many grams of carbon dioxide are produced?

198.45 g CO₂

Explanation:

dа ta:

The equation for combustion is given as follows:

C3H8 + 5O2 = 3CO2 + 4H2O

Number of moles of C₃H₈ burned = 1.50

Number of moles of CO₂ formed = 3 (1.50)

= 4.50 moles

mass of CO₂ = number of moles * Mr

= 4.50 * 44.10

= 198.45 grams

1.50 mol C3H8 X (3 mol CO2 / 1 mol C3H8) X (44.0 g CO2 / 1 mol CO2) = 198 g CO2