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2 February, 22:50

calculate the amount of heat energy required to evaporate 25.7g of water at 100 degrees celcius. (Molar heat of vaporization of liquid water = 4.07x10^4 J/mol)

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  1. 2 February, 22:52
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    5.82 * 10⁴ j

    Explanation:

    Given dа ta:

    Mass of water = 25.7 g

    Amount of heat to evaporate it = ?

    Molar heat of vaporization = 4.07*10⁴ j/mol

    Solution:

    First of all we will calculate the number of moles of water.

    Number of moles = mass / molar mass

    Number of moles = 25.7 g / 18 g/mol

    Number of moles = 1.43 mol

    Energy needed for one mole is 4.07*10⁴ j.

    For 1.43 mol:

    1.43 mol * 4.07*10⁴ j / 1mol

    5.82 * 10⁴ j
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