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10 June, 08:56

What is the mass of 1.63 moles and f ammonium phosphorus (NH4) 3PO4

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  1. 10 June, 09:05
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    mass (NH4) 3PO4 = 243.011 g

    Explanation:

    mass (NH4) 3PO4 = ?

    ∴ moles (NH4) 3PO4 = 1.63 moles

    ∴ molecular weight (Mw) = 149.0867 g/mol

    mass = (mol) * (Mw)

    ⇒ mass (NH4) 3PO4 = (1.63 mol (NH4) 3PO4) * (149.0867 g/mol)

    ⇒ mass (NH4) 3PO4 = 243.011 g
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