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18 April, 09:45

Suppose you wanted to heat a mug of water (178 mL) from room temperature 10 °C to 52 °C to make a cup of tea. How much energy (in units of joules) would you need from your microwave? (Cwater=4.184 J/g˚C)

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  1. 18 April, 10:11
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    Q = 31279.6 j

    Explanation:

    Given dа ta:

    Mass = 178 mL

    Initial temperature = 10°C

    Final temperature = 52°C

    Specific heat capacity = 4.184 j/g.°C

    Heat absorbed = ?

    Solution:

    First of all we will convert the mL to g.

    178 mL*1 L/1000 mL = 0.178 L

    1 L = 1000 g

    0.178 * 1000 = 178 g

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = T2 - T1

    ΔT = 52°C - 10°C

    ΔT = 42°C

    Q = m. c. ΔT

    Q = 178 g * 4.184 J/g.°C * 42°C

    Q = 31279.6 j
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