What is the mass of strontium chloride that reacts with 300.0 g of sulfuric acid?

SrCl₂ reacts with conc. H₂SO₄ and gives SrSO₄ and 2HCl as the products. The balanced equation is

SrCl₂ + H ₂SO₄ → SrSO ₄ + 2HCl

moles = mass / molar mass

molar mass of H₂SO₄ = 98 g mol⁻¹

moles of H₂SO₄ = 300.0 g / 98 g mol⁻¹ = 3.06 mol

Stoichiometric ratio between SrCl₂ and H₂SO₄ is 1 : 1

Hence, moles of SrCl₂ = moles of H₂SO₄

= 3.06 mol

molar mass of SrCl₂ = 158.53 g mol⁻¹

Hence, mass of SrCl₂ = 3.06 mol x 158.53 g mol⁻¹

= 485.1 g

Hence, the mass of SrCl₂ needed to react with H₂SO₄ is 485.1 g