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Jasiah Travis
Chemistry
3 March, 02:50
Solve 2v^2-90=0, where v is a real number
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Chace Travis
3 March, 02:57
0
First thing you want to do is put v by itself
Add 90 to both sides
2v^2 = 90
Divide by 2 on both sides
v^2 = 45
And then take the sqrt (45)
v = sqrt (45)
We can reduce this by finding the perfect square which is 9
v = sqrt (9) * sqrt (5)
So,
v = 3 * sqrt (5)
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