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27 March, 14:56

How much energy is required to decompose 800 g of pcl3, according to the reaction below? the molar mass of pcl3 is 137.32 g/mol and may be useful. 4 pcl3 (g) → p4 (s) + 6 cl2 (g) δh∘rxn = + 1207 kj how much energy is required to decompose 800 of, according to the reaction below? the molar mass of is 137.32 and may be useful. 4 (g) (s) + 6 (g) = + 1207 1.76*103 kj 4.53*103 kj 2.31*103 kj 6.72*103 kj 5.90*103 kj?

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  1. 27 March, 15:09
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    First, we have to get the no. of moles of PCl3:

    no. of moles of PCl3 = mass/molar mass of PCl3

    when we have mass = 800 g & molar mass of PCl3 = 137.32 g / mol

    so by substitution:

    no. of moles of PCl3 = 800 g / 137.32 g/mol

    = 5.83 mol

    from the balanced equation:

    4PCl3 (g) → P4 (s) + 6Cl (g) ΔH = + 1207 KJ

    we can see that 4 mol of PCl3 need 1207 KJ to be decomposed

    So 5.83mol of PCl3 need X KJ?

    ∴energy required = 1207 KJ * 5.83 mol / 4 mol

    =1.76*10^3 KJ
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