The synthesis of methanol from carbon monoxide and hydrogen gas is described by the following chemical equation:

CO (g) + 2H2 (g) ? CH3OH (g)

The equilibrium constant for this reaction at 25? Cis Kc=2.3*104. In this tutorial, you will use the equilibrium-constant expression to find the concentration of methanol at equilibrium, given the concentration of the reactants.

The equilibrium-constant expression is a mathematical equation that can be rearranged to solve for any of the variables in it. Rearrange the equilibrium-constant expression to solve for [CH3OH].

Kc[CO][H2]^2

Suppose that the molar concentrations for CO and H2 at equilibrium are [CO] = 0.02 M and [H2] = 0.06 M.

Use the formula you found in Part B to calculate the concentration of CH3OH.

Express your answer to one decimal place and include the appropriate units.

Question

Macey George

Chemistry

10 April, 15:05

The synthesis of methanol from carbon monoxide and hydrogen gas is described by the following chemical equation:

CO (g) + 2H2 (g) ? CH3OH (g)

The equilibrium constant for this reaction at 25? Cis Kc=2.3*104. In this tutorial, you will use the equilibrium-constant expression to find the concentration of methanol at equilibrium, given the concentration of the reactants.

The equilibrium-constant expression is a mathematical equation that can be rearranged to solve for any of the variables in it. Rearrange the equilibrium-constant expression to solve for [CH3OH].

Kc[CO][H2]^2

Suppose that the molar concentrations for CO and H2 at equilibrium are [CO] = 0.02 M and [H2] = 0.06 M.

Use the formula you found in Part B to calculate the concentration of CH3OH.

Express your answer to one decimal place and include the appropriate units.

+5

Answers (1)

Know the Answer?

Kenley · Answer 1

[CH3OH (g) ] = 1.7 M

Explanation:

CO (g) + 2H2 (g) ↔ CH3OH (g)

∴ Kc (25°C) = 2.3 E4 = [CH3OH (g) ] / [CO (g) ]*[H2 (g) ]²

⇒ [CH3OH (g) ] = Kc.[CO (g) ][H2 (g) ]²

∴ [CO (g) ] = 0.02 M

∴ [H2 (g) ] = 0.06 M

⇒ [CH3OH (g) ] = (2.3 E4) (0.02) (0.06) ²

⇒ [CH3OH (g) ] = 1.7 M