How many phosphorus atoms are contained in 158 kg of phosphorus? how many phosphorus atoms are contained in 158 kg of phosphorus? 3.07 * 1027 phosphorus atoms 2.95 * 1027 phosphorus atoms 1.18 * 1024 phosphorus atoms 3.25 * 1028 phosphorus atoms 8.47 * 1024 phosphorus atoms?

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Catalina Rogers

Chemistry

8 December, 03:36

How many phosphorus atoms are contained in 158 kg of phosphorus? how many phosphorus atoms are contained in 158 kg of phosphorus? 3.07 * 1027 phosphorus atoms 2.95 * 1027 phosphorus atoms 1.18 * 1024 phosphorus atoms 3.25 * 1028 phosphorus atoms 8.47 * 1024 phosphorus atoms?

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Ayana Mueller · Answer 1

To determine the number of phosphorus atoms from a given mass, we need to determine the number of moles of the substance by dividing the molar mass which for in this case is equal to 123.88 g/mol for P4. Then, we multiply Avogadro's number. It represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole.

mole P4 = 158 kg P4 (1000 g / 1 kg) (1 mol / 123.88 g) = 1275.43 mol P4

# of P4 atoms = 1275.43 mol P4 (6.022 x 10^23 atoms P4 / 1 mol P4) = 7.68x10^26 atoms P4