Determine the number of ch2cl2 molecules in 25.0 g ch2cl2. determine the number of ch2cl2 molecules in 25.0 g ch2cl2.

Question

Ramiro Shelton

Chemistry

10 October, 04:33

Determine the number of ch2cl2 molecules in 25.0 g ch2cl2. determine the number of ch2cl2 molecules in 25.0 g ch2cl2.

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Answers (1)

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Elaine Campos · Answer 1

Answer is: there is 1,77·10²³ molecules of CH₂Cl₂.

m (CH₂Cl₂) = 25 g.

n (CH₂Cl₂) = m (CH₂Cl₂) : M (CH₂Cl₂).

n (CH₂Cl₂) = 25 g : 85 g/mol.

n (CH₂Cl₂) = 0,294 mol.

N (CH₂Cl₂) = n (CH₂Cl₂) · Na.

N (CH₂Cl₂) = 0,294 mol · 6,023 1/mol.

N (CH₂Cl₂) = 1,77·10²³.

n - amount of substance.

Na - Avogadro number.