How much HCl is produced from the reaction of an excess of HSbCl4 with 3 moles H2S in the following reaction? HSbCl4 + H2S → Sb2S3 + HCl (Remember to balance the equation.)

We will produce 8.0 moles of HCl, this is 291.7 grams HCl

Explanation:

Step 1: Data given

Number moles of H2S = 3.0 moles

Step 2: The balanced equation

2HSbCl4 + 3H2S → Sb2S3 + 8HCl

Step 3: Calculate moles HCl

For 2 moles HSbCl4 we need 3 moles H2S to produce 1mol Sb2S3 and 8 moles HCl

For 3.0 moles H2S we'll have 8.0 moles HCl

Step 4: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 8.0 moles * 36.46 g/mol

Mass HCl = 291.7 grams

We will produce 8.0 moles of HCl, this is 291.7 grams HCl