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27 May, 16:32

How much heat is required to raise the temperature of a 4.33-g sample of iron (specific heat = 0.450 J/g°C) from 25.0°C to 79.8°C?

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  1. 27 May, 16:37
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    106.78 J of heat is required by the iron sample.

    Explanation:

    We have to find the amount of heat required using the formula,

    q = m * c * ΔT

    where q is the heat absorbed

    m is mass of the metal in grams = 4.33 g

    c = specific heat of iron = 0.450 J/g °C

    ΔT = change in temperature = 79.8° C - 25°C = 54.8° C

    Plugin the values in the above formula, we will get,

    q = 4.33 g * 0.450 J/g° C * 54.8° C

    = 106.78 J

    So 106.78 J of heat is required by the sample of iron.
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