When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from oC to 87°C

The answer:

When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from? oC to 87°C

application of charles law

charle's law tells that

T1 / V1 = T2 / V2, T must be in kelvin

it is given that V1 = 3.6 L, V2 = 15.5 L,

T2 = 87°C = 360.15 K

so to find T1, T1 = (T2 / V2) x V1

T1 = (360.15 / 15.5) * 3.6 = 83.64° K = - 190.15° C