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13 November, 15:08

What is the final volume of a 400 ML sample that is subjected To a temperature change from 22 Celsius to 30 Celsius in a pressure change from 760 am MHG to 360 MMHG

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  1. 13 November, 15:27
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    The answer to your question is V2 = 867.3 mL

    Explanation:

    Data

    Volume 1 = V1 = 400 ml

    Temperature 1 = T1 = 22°C

    Pressure 1 = P1 = 760 mmHg

    Volume 2 = V2 = ?

    Temperature 2 = T2 = 30°C

    Pressure 2 = P2 = 360 mmHg

    Process

    1. - Convert Celsius to Kelvin

    T1 = 22 + 273 = 295°K

    T2 = 30 + 273 = 303°K

    2. - Use the Combined gas law

    P1V1/T1 = P2V2/T2

    - Solve for V2

    V2 = P1V1T2 / T1P2

    - Substitution

    V2 = (760 x 400 x 303) / (295 x 360)

    - Simplification

    V2 = 92112000 / 106200

    -Result

    V2 = 867.3 mL
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