Ask Question
11 June, 18:42

What is the limiting reagent when 49.84 g of nitrogen react with 10.7 g of hydrogen according to this balanced equation: n2 (g) 3h2 (g) → 2nh3 (g) ?

+1
Answers (1)
  1. 11 June, 18:58
    0
    Moles of nitrogen = 49.84 / 28 = 1.78

    Moles of hydrogen = 10.7 / 2 = 5.35

    Molar ratio of nitrogen to hydrogen = 1 : 3

    Hydrogen required = 1.78 x 3 = 5.34

    Therefore, hydrogen is in excess and nitrogen is the limiting reagent.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the limiting reagent when 49.84 g of nitrogen react with 10.7 g of hydrogen according to this balanced equation: n2 (g) 3h2 (g) → ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers