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29 March, 21:28

Given that cao (s) + h2o (l) → ca (oh) 2 (s), δh°rxn = - 64.8 kj/mol, how many grams of cao must react in order to liberate 525 kj of heat?

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  1. 29 March, 21:49
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    454.3 g.

    Explanation:

    From the given dа ta:

    1.0 mol of CaO liberates → - 64.8 kJ.

    ? mol of CaO liberates → - 525 kJ.

    ∴ The no. of moles needed = (1.0 mol) ( - 525 kJ) / ( - 64.8 kJ) = 8.1 mol.

    ∴ The no. of grams of CaO needed = no. of moles x molar mass = (8.1 mol) (56.077 g/mol) = 454.3 g.
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