The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of water are R = 0.4615 kPa·m3/kg·K, Tcr = 647.1 K, and Pcr = 22.06 MPa. Determine the specific volume of superheated water based on the ideal-gas equation. (You must provide an answer before moving to the next part)

Question

Apple Jack

Chemistry

6 April, 11:49

The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of water are R = 0.4615 kPa·m3/kg·K, Tcr = 647.1 K, and Pcr = 22.06 MPa. Determine the specific volume of superheated water based on the ideal-gas equation. (You must provide an answer before moving to the next part)

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Abraham Moody · Answer 1

0.01917 m^3/kg.

Explanation:

Given:

P = 15 MPa

= 1.5 * 10^4 kPa

T = 350 °C

= 350 + 273

= 623 K

Molar mass of water, m = (2 * 1) + 16

= 18 g/mol

= 0.018 kg/mol

R = 0.4615 kPa·m3/kg·K

Using ideal gas equation,

P * V = n * R * T

But n = mass/molar mass

V = (R * T) / P

V/M = (R * T) / P * m

= (0.4615 * 623) / 1.5 * 10^4

= 0.01917 m^3/kg.